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At a distance of 41 ft , an ionizing radiation source delivers 5.0 rem of radiation. How close could you get to the source and still have no biological effects? Express your answer to two significant figures and include the appropriate units.

Respuesta :

Answer:

at distance 18.33 ft no biological effects

Explanation:

given data

distance = 41 ft

radiation = 5 rem

to find out

how close get so no biological effects

solution

we know here that intensity of radiation R is inversely proportional to (radiation)²

so here equation will be

[tex]\frac{I1}{I2}  = (\frac{R2}{R1})^{2}[/tex]   .............1

here I is intensity

so here I1 = 25

because for  0 to 25 there is  no detectable effects and for 25 to 100 it will . temporary decrease so

we take 25 because dose is less than 25 so we take that highest value

so

[tex]\frac{I1}{I2}  = (\frac{R2}{R1})^{2}[/tex]

[tex]\frac{25}{5}  = (\frac{41}{R1})^{2}[/tex]

R1 = 18.33 ft

so at distance 18.33 ft no biological effects

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