Answer:
The helicopter was 1103.63 meters high when the package was dropped.
Explanation:
We consider positive speed as a downward movement
y: height (m)
t: time (s)
v₀: initial speed (m/s)
Δy = v₀t + [tex]\frac{1}{2}[/tex]gt²
Δy= 15[tex]\frac{m}{s}[/tex]×15 s + [tex]\frac{1}{2}[/tex]×9.81[tex]\frac{m}{s^{2} }[/tex]×(15 s)²
Δy= 1103.63 m
