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Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74 J/g·K. If 16.7 kJ of energy is absorbed by a 225-g sample of benzene at 20.0°C, what is its final temperature? *HINT check what number the question is asking for>

A. –22.7°C
B. 36.7°C
C. 42.7°C
D. 62.7°C
E. none of these choices is correct

Respuesta :

Answer: [tex]62.7^0C[/tex]

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed= 16.7 kJ = 16700 J  (1kJ=1000J)

m= mass of benzene = 225 g

c = specific heat capacity = 1.74 J/gK

Initial temperature of the water = [tex]T_i[/tex] = 20.0°C  = 293 k  [tex]0^0C=273K[/tex]

Final temperature of the water = [tex]T_f[/tex]  = ?

Change in temperature ,[tex]\Delta T=T_f-T_i[/tex]

Putting in the values, we get:

[tex]16700=225\times 1.74\times (T_f-293)[/tex]

[tex]T_f=335.6K=62.7^0C[/tex]

The  final temperature will be [tex]62.7^0C[/tex]