Answer:
v = 49.69 km/hr
Explanation:
velcoity of truck with respect to car is given as = velocity of truck - velocity of car
velcoity of truck with respect to car is given as = (-54 sin(28)i +54cos(28)j - 91km/h
= -24.35i - 43.32j
magnitude of velocity is
[tex]v = \sqrt{ 24.35^2+43.32^2}[/tex]
v = 49.69 km/hr
the direction is
[tex]tan^{-}[\frac{ 43.32}{24.35}][/tex]
= 60.65 degree towrd south of west
