Respuesta :

gmany

Answer:

[tex]\left[\begin{array}{ccc}1\\-1\end{array}\right] \times\left[\begin{array}{ccc}0&4\end{array}\right][/tex]

Step-by-step explanation:

To be able to multiply two matrices, the number of columns in the first matrix must be the same as the number of rows in the second matrix.

(1)

first matrix: 2 columns

second matrix: 1 row

NOT

(2)

first matrix: 1 column

second matrix: 2 rows

NOT

(3)

first matrix: 2 columns

second matrix: 1 row

NOT

(4)

first matrix: 1 column

second matrix: 1 row

YES

[tex]\left[\begin{array}{ccc}1\\-1\end{array}\right] \times\left[\begin{array}{ccc}0&4\end{array}\right] =\left[\begin{array}{ccc}(1)(0)&(1)(4)\\(-1)(0)&(-1)(4)\end{array}\right] =\left[\begin{array}{ccc}0&4\\0&-4\end{array}\right][/tex]

We want to see which of the given multiplications are possible, we will see that the correct options are the second and last ones (counting from the top)

Multiplication of matrices.

We define a matrix as an M×N construction, so the matrix has M rows and N columns.

Two matrices can only be multiplied if the second matrix has the same number of rows than the first one of columns.

So if:

A is a matrix M×N

B is a matrix M×K

We can't multiply A*B, because B does not have the same number of rows as A has of columns. if instead, B was N×K, the multiplication would be possible.

So now that we know that is easy to see which multiplications are allowed.

The 2nd one we have:

1×2 times  2×2

So this is allowed.

The final one:

1×2 times 2×1

So this is allowed.

Then the correct options are the second and fourth ones, counting from the top.

If you want to learn more about the product of matrices, you can read:

https://brainly.com/question/1821869