A kangaroo jumps straight up with an initial vertical velocity of 2.4\,\dfrac{\text{m}}{\text{s}}2.4 sm​ 2, point, 4, space, start fraction, m, divided by, s, end fraction. We want to find the maximum height of the jump.

Respuesta :

Answer:

it can jump upto maximum height of 0.29 m

Explanation:

Initial velocity of the Kangaroo when it jumps upwards is given as

[tex]v_i = 2.4 m/s[/tex]

final velocity of the kangaroo is given as

[tex]v_f = 0[/tex]

now we know that acceleration is due to gravity

[tex]a = -g[/tex]

now in order to find maximum height we know that we can use kinematics equation

[tex]v_f^2 - v_i^2 = 2a d[/tex]

[tex]0 - 2.4^2 = 2(-9.81) d[/tex]

[tex]d = 0.29 m[/tex]

so it can jump upto maximum height of 0.29 m