Answer:
At any time t, her altitud will be given by the following law:
[tex]y=0 + 4.73\frac{m}{s}\cdot t - \frac{1}{2} g\cdot t^{2}[/tex]
Explanation:
We can consider the gymnast as a point particle in the position of her center of mass. The law of movement will be:
[tex]y=0 + 4.73\frac{m}{s}\cdot t - \frac{1}{2} g\cdot t^{2}[/tex]
where g is gravity's acceleration which we can take as [tex]g=9.8\frac{m}{s^{2} }[/tex]. We add 0 in the last member just to note that at [tex]t=0[/tex] the vertical position is 0. If we knew that she was moving at [tex]4.73\frac{m}{s}[/tex] at [tex]1m[/tex], we would have needed to put 1m in the place of 0.
