What sum of money will grow to $3,184.41 in nine years at 3% compounded monthly?

Select one:

a. $2,431.73

b. $2,517.88

c. $2,520.41

d. $2,498.47

Respuesta :

Answer:

P = $2,431.73

Step-by-step explanation:

The compound interest formula is given by:

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

In this exercise, we have:

A = 3,184.41

r = 0.03

n = 12(t is measured in years, and the money is compounded monthly)

t = 9

We want to know P

[tex]P = \frac{A}{(1 + \frac{r}{n})^{nt}}[/tex]

[tex]P = \frac{3,184.41}{(1 + \frac{0.03}{12})^{12*9}}[/tex]

[tex]P = \frac{3,184.41}{(1 + 0.0025)^108}[/tex]

[tex]P = \frac{3,184.41}{1.31}[/tex]

[tex]P = $2,431.73[/tex]