There are [tex]1.96 \times 10^{21}}[/tex] atoms in the 91.5 mg of iron. A mole is equal to the number of ions, atoms, or molecules as present in 12 g of C-12 which is equal to the [tex]6.02 \times 10^2^3[/tex]
A mole is equal to the number of ions, atoms, or molecules as present in 12 g of C-12 which is equal to the [tex]6.02 \times 10^2^3[/tex]
The formula of the mole is:
[tex]n = \dfrac wm[/tex]
Where,
[tex]n[/tex]- number of moles
[tex]w[/tex] - given mass = 91.5 mg = 0.0915 g
[tex]m[/tex] - molar mass = 27.98 g/mol
Put the values in the formula,
[tex]n = \dfrac {0.0915}{27.98 }\\\\n = 0.00327[/tex] mole
Now,
[tex]\bold {number\; of\ atoms= \ 6.02 \times 10^2^3\times 0.00327}\\\\\bold{number\; of\ atoms= 1.96 \times 10^{21}}[/tex]
Therefore, there are [tex]1.96 \times 10^{21}}[/tex] atoms in the 91.5 mg of iron.
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