Answer:
Number of moles = 0.256*0.895 as M = moles/liter so 0.229 moles.
And NH4Cl has mol. wt. of 14+4*1+35.5 = 53.5 g/mole.
So 53.5*0.229 g = 12.3 g
11.98 g is the mass of solute is contained in 256mL of a 0.875 M ammonium chloride solution.
Molarity of a solution can be calculated as:
M = n/V, where
n = no. of moles
V = volume of solution = 256mL = 0.256L
Given molarity of solution = 0.875M
Now we calculate the moles by putting values in the above equation, we get
n = M × V
n = 0.875 × 0.256 = 0.224 moles
Now we calculate the mass of NH₄Cl, by using the below formula:
n = W/M,
W = required mass
M = molar mass = 53.491g/mole
W = 0.224 × 53.491 = 11.98 g
Hence, mass of solute is 11.98 g.
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