Answer:
21.35 cm^3
Explanation:
let the volume at the surface of fresh water is V.
The volume at a depth of 100 m is V' = 2 cm^3
temperature remains constant.
density of water, d = 1000 kg/m^3
Pressure at the surface of fresh water is atmospheric pressure,
P = Po = 1.013 x 10^5 N/m^2
The pressure at depth 100 m is P' = Po + hdg
P' = [tex]1.013 \times 10^{5}+ 100 \times 1000 \times 9.8[/tex]
P' = 10.813 x 10^5 N/m^2
Use the Boyle's law
P V = P' V'
[tex]1.013 \times 10^{5}\times V = 10.813 \times 10^{5}\times 2[/tex]
V = 21.35 cm^3
Thus, the volume of air bubble at the surface of fresh water is 21.35 cm^3.
