Answer:
66.26 m/s
Explanation:
Horizontal velocity, Vx = 55.3 m/s
Vertical velocity, Vy = 36.5 m/s
The value of the resultant velocity is given by the vector sum of the two velocities which are acting at 90°.
[tex]V=\sqrt{V_{x}^{2}+V_{y^{2}}}[/tex]
[tex]V=\sqrt{55.3^{2}+36.5^{2}}}[/tex]
V = 66.26 m/s
Thus, the velocity of the vehicle is 66.26 m/s along its descent path.