Carbon disulfide (n = 1.63) is poured into a container made of sodium chloride (n = 1.54). What is the critical angle for total internal reflection of a light ray in the liquid when it is incident on the liquid-to-glass surface?

Respuesta :

Answer:

70.87°

Explanation:

The formula for the critical angle is:

[tex]{sin\theta_{critical}}=\frac {n_r}{n_i}[/tex]

Where,  

[tex]{\theta_{critical}}[/tex] is the critical angle

[tex]n_r[/tex] is the refractive index of the refractive medium.

[tex]n_i[/tex] is the refractive index of the incident medium.

n₁ is the refractive index for Carbon disulfide which is 1.63 (incident medium)  

n₂ is the refractive index of sodium chloride which is 1.54 (refractive medium)

Applying in the formula as:

[tex]{sin\theta_{critical}}=\frac {1.54}{1.63}[/tex]

The critical angle is = sin⁻¹ 0.9448 = 70.87°