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A battery operating a large flashlight produces a current of 2 amperes in a lightbulb that has a resistance of 2.4 ohms. The voltage of the battery is:

Respuesta :

Answer:

Voltage of the battery = 4.8 volt

Explanation:

It is given that the flashlight produces a current of 2 ampere

So current  i = 2A

And the resistance R = 2.4 ohm

We have to find the voltage of the battery

According to ohm's law voltage of the battery is given by = current × resistance

So voltage = 2×2.4 =4.8 volt

The voltage of the battery depends on the current and resistance.

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