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What would be the pressure (in atmospheres) exerted by 0.75 moles of an ideal gas, if the gas filled a 40.5 liter container at a temperature of 19 degrees Celsius? (The ideal gas constant is 0.0821 L•atm/mol•K.)

Respuesta :

Answer:

P  = 0.44 atm

Explanation:

given data:

gas constant R = 0.0821 L.atm/mol. k

Temperature = 19 degree celcius = 19+273 = 292 K

Volume = 40.5 L

FROM IDEAL GAS EQUATION IS WE  HAVE

mole n = 0.75

[tex]P = \frac{nRT}{V}[/tex]

putting all value to get the desired value to get desired pressure value.

[tex]= \frac{(0.75)*( 0.0821)*(292)}{(40.5 L)}[/tex]

P  = 0.44 atm

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