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Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 60 mi/h. (a) Assuming they start at the same point, how much sooner does the faster car arrive at a destination 6 mi away? min

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thedemon840

Answer:

The first car arrives (33 seconds or 0.55 minutes) earlier

Explanation:

Firstly calculate the time taken by (60 mi/h) car to reeach the destination;

; Time taken = Distance/Speed

; Time taken = 6 ÷ 60 = 0.1h

Hence 0.1h = 6 minutes

Then the time taken by the (55mi/h) car to reach the destination;

; Time taken = 6 ÷ 55 = 0.1091h

Hence 0.1091h = 6.55 minutes

Therefore...time difference

; 6.55 - 6 = 0.55 minutes/33 seconds

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