Answer:
The minimum velocity required is 7.923 m/s
Explanation:
The minimum speed required shall be equal to the speed that allows the camera to just reach a height of 3.2 meters
This can be solved using the third equation of kinematics as
[tex]v^{2}=u^{2}+2gs[/tex]
where
v = final speed of object
u = initial speed of object
s = is the height attained
Since finally velocity becomes zero thus the above equation reduces to
[tex]0=u^{2}-2\times 9.81\times 3.2\\\\\therefore u=\sqrt{2\times 9.81\times 3.2}\\\\u=7.923m/s[/tex]
