Respuesta :
Explanation:
Given that,
Angular velocity = 0.240 rev/s
Angular acceleration = 0.917 rev/s²
Diameter = 0.720 m
(a). We need to calculate the angular velocity after time 0.203 s
Using equation of angular motion
[tex]\omega_{f}=\omega_{i}+\alpha t[/tex]
Put the value in the equation
[tex]\omega_{f}=0.240+0.917\times0.203[/tex]
[tex]\omega_{f}=0.426\ rev/s[/tex]
The angular velocity is 0.426 rev/s.
(b). We need to calculate the tangential speed of the blade
Using formula of tangential speed
[tex]v= r\omega[/tex]
Put the value into the formula
[tex]v = \dfrac{0.720 }{2}\times0.426\times2\pi[/tex]
[tex]v=0.963\ m/s[/tex]
The tangential speed of the blade is 0.963 m/s.
(c). We need to calculate the magnitude at of the tangential acceleration
Using formula of tangential acceleration
[tex]a_{t}=r\alpha[/tex]
Put the value into the formula
[tex]a_{t}=0.36\times0.917\times2\pi[/tex]
[tex]a_{c}=2.074\ m/s^2[/tex]
The tangential acceleration is 2.074 m/s².
Hence, This is required solution.
(a) The final angular velocity of the fan blade is 2.68 rad/s.
(b) The tangential speed of the blade at a point on the tip of the blade is 0.965 m/s.
(c) The tangential acceleration of the blade is 2.07 m/s².
Final angular velocity of the fan blade
The final angular velocity of the fan blade is calculated as follows;
ωf = ω₀ + αt
ωf = (0.24 x 2π) + (0.917 x 2π)(0.203)
ωf = 2.68 rad/s
Tangential speed of the blade
The tangential speed of the blade at a point on the tip of the blade is calculated as follows;
v = ωf x (0.72/2)
v = 2.68 x 0.36
v = 0.965 m/s
Tangential acceleration
The tangential acceleration is calculated as follows;
[tex]a_t =\alpha r\\\\\a_t = (0.917 \times 2\pi) \times 0.36\\\\a_t =2.07 \ m/s^2[/tex]
Learn more about tangential speed here: https://brainly.com/question/19660334