Answer:
The distance is 51.42 meters.
The time is 17.14 seconds approximately.
Explanation:
from the following relation.
vf^2 = vi^2 + 2 * a * d
Where vf is final velocity
a is acce;eration
d is distance to which swan traveled
vi = 0 { accelerate from rest}
6.00^2 = 2 * 0.350 * d
d =\frac{36}{.7}
The distance is 51.42 meters.
(b)
Use the following equation.
d = ½ * (vi + vf) * t
51.42= ½ * 6.0 * t [tex]t = \frac{51.42*2}{6}[/tex]
The time is 17.14 seconds approximately.
