Answer : The correct option is, (B) [tex]H_2SO_3,HSO_3^-[/tex]
Explanation :
According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.
Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.
The given equilibrium reaction is,
[tex]H_2SO_3(aq)+CN^-\rightleftharpoons HSO_3^-(aq)+HCN(aq)[/tex]
Here, [tex]H_2SO_3[/tex] is loosing a proton, thus it is considered as an acid and after losing a proton, it forms [tex]HSO_3^{-}[/tex] which is a conjugate base. That means, [tex]H_2SO_3/HSO_3^-[/tex] are act as a conjugate acid-base pairs.
Hence, correct option is, (B) [tex]H_2SO_3,HSO_3^-[/tex]
