Respuesta :
Answer:
total time =4.583 hour
Explanation:
We have given total distance = 60 mi
It is given that half of the distance traveled by a speed of 8 mph
We know that [tex]time\ t=\frac{distance }{speed}=\frac{30}{8}=3.75hour[/tex]
And second half of the distance traveled by a speed of 36 mph
So time [tex]t=\frac{distance }{speed}=\frac{30}{36}=0.833hour[/tex]
So total time = 3.75 + 0.833 =4.583 hour
Answer:
t = 4.58 hours
Explanation:
car trip = 60 miles
first half trip of 30 mile at 8 mph.
second half of 30 mile at 36 mph.
distance = speed × time
[tex]time = \dfrac{distance}{speed}[/tex]
for first half time taken
[tex]t_1 = \dfrac{30}{8}[/tex]
[tex]t_1 = 3.75\ hours[/tex]
for second half distance time taken
[tex]t_2 = \dfrac{30}{36}[/tex]
[tex]t_2 = 0.833\ hours[/tex]
total time taken
t = t₁ + t₂
t = 3.75 + 0.833
t = 4.58 hours
