Respuesta :
Answer:
total volume = 0.9125 m³
Explanation:
given data
volume = 28 litres
pressure 2 = 40 MPa
pressure 3 = 35 MPa
pressure 1 = 30 MPa
y = 1.4
to find out
total volume of the accumulator
solution
we know here oil deliver 28 litter
so V3 - V2 = 28 litter
so V3 = V2 + 28
V3 = V2 + 0.028
and we know
volume 1 = V2 × [tex](\frac{P2}{P1})^{1/y}[/tex] ................1
and volume 2 = V3 × [tex](\frac{P3}{P2})^{1/y}[/tex] ..................2
put here value
volume 2 = V3 × [tex](\frac{P3}{P2})^{1/y}[/tex]
volume 2 = (V2 + 0.028) × [tex](\frac{35}{40})^{1/1.4}[/tex]
volume V2 = 0.274 m³
and from equation 1
volume 1 = V2 × [tex](\frac{P2}{P1})^{1/y}[/tex]
volume 1 = 0.274 × [tex](\frac{40}{30})^{1/y}[/tex]
volume 1 = 0.3365 m³
and
volume V3 = V2 + 0.028
volume V3 = 0.274 + 0.028
volume V3 = 0.302 m³
so total volume = V1 + V2 + V3
total volume = 0.274 + 0.3365 + 0.302
total volume = 0.9125 m³
