Answer:
3.3m/s
Explanation:
1. Find the acceleration a:
Given: normal force: N, the horizontal force: F, friction coefficient: μ, mass: m, acceleration of gravity: g. The sum of all forces in the horizontal plane is:
∑F = ma = F - μN = F - μmg
Solve for the acceleration a:
(i) a = F/m - μg
2. Use the equations of motion to calculate the velocity v for a uniform acceleration a, time t and initial velocity v₀:
(ii) v = at + v₀
position x, initial position x₀:
(iii) x = 0.5at² + v₀t + x₀
Eliminate time t by plugging in eq. (ii) into eq. (iii) with v₀ = 0 and x₀ = 0:
(iv) x = 0.5v²/a
Solve for v:
(v) v = √(2xa) = √(2*x*( F/m - μg)) = √(2*4.89 * (14.4/5.86 - 0.14*9.8))
