Answer:
[tex]f^{-1}(x)[/tex]=the quantity of 3x plus 5 divided by 2
Step-by-step explanation:
We are given that a function [tex]f(x)=\frac{2x-5}{3}[/tex]
We have to find the correct expression
Suppose y=[tex]\frac{2x-5}{3}[/tex]
[tex]3y=2x-5[/tex]
[tex]3y+5=2x[/tex]
[tex]x=\frac{3y+5}{2}[/tex]
Therefore, [tex]f^{-1}(x)=\frac{3x+5}{2}[/tex]
Answer:[tex]f^{-1}(x)[/tex]=the quantity of 3x plus 5 divided by 2
