Respuesta :
Answer:
the following is 5x^2 + 32x - 21
(5x - 3)(x + 7)
5x^2 + 35x - 3x - 21
5x^2 + 32x - 21
The area of the rectangle = [tex]5 x^{2}+32 x-21[/tex].
What is the area of the rectangle?
Area of the rectangle = Length [tex]*[/tex] Width
where L is the length of the rectangle
W be the width of the rectangle
In this problem we have
Length = (5x - 3) units
Width = (x + 7) units
Substitute the values of length and width in the formula to find the area of the rectangle
Area of the rectangle = Length [tex]*[/tex] Width
Area of the rectangle = (5x - 3)(x + 7)
A = (5x - 3)(x + 7)
Multiplying the parenthesis, then we get
A = 5x [tex]*[/tex] x + 5x [tex]*[/tex] 7 - 3x - 3 [tex]*[/tex] 7
Simplifying the above equation, we get
[tex]${data-answer}amp;A=5 x^{2}+35 x-3 x-21 \\[/tex]
[tex]${data-answer}amp;A=5 x^{2}+32 x-21[/tex]
The area of the rectangle = [tex]5 x^{2}+32 x-21[/tex].
Therefore, the correct answer is option C. [tex]5 x^{2}+32 x-21[/tex].
To learn more about the area of the rectangle
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