Answer:
option A
Explanation:
given,
shear force = 425 N
Shear modulus = 1.7 × 10⁹ N/m²
disk equivalent to solid cylinder
height = 0.7 cm and diameter = 6.50 cm
[tex]\delta = \dfrac{VL}{AG}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi d^2\times 1.7\times 10^9}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi\times 0.065^2\times 1.7\times 10^9}\\\\\delta = 5.27 \times 10^{-7} m[/tex]
hence, the correct answer is option A
