Answer:
The power of his ideally prescribed eyeglasses is 1.0 D.
Explanation:
Given that,
Image distance = 110 cm
We know that,
Object distance = ∞
We need to calculate the focal length
Using formula of lens
[tex]\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}[/tex]
Put the value into the formula
[tex]\dfrac{1}{f}=\dfrac{1}{-110}+\dfrac{1}{\infty}[/tex]
[tex]f=-110\ cm[/tex]
We need to calculate the power of his ideally prescribed eyeglasses
Using formula of power
[tex]P=\dfrac{100}{f}[/tex]
[tex]P=\dfrac{100}{110}[/tex]
[tex]P=0.90 = -1.0\ D[/tex]
Hence, The power of his ideally prescribed eyeglasses is 1.0 D.
