Answer:
K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹
Explanation:
Rate of flow of heat through a material is given by the following expression
[tex]\frac{Q}{t} =\frac{KA\delta T}{d}[/tex]
where Q is amount of heat flowing in time t through area A and a medium of thickness d having two faces at temperature difference δT . K is thermal conductivity of the medium .
Here Q = 3.34 x 10⁶/6 , t = 24 x 60 x 60 = 86400 s , A = .332 X .332 = .0110224 m² , δT = 104.7
Put these values here
[tex]\frac{3.34\times10^6}{6\times86400}= \frac{k\times.011224\times104.7}{4.41\times10^{-2}}[/tex]
[tex]K=\frac{3.34\times4.41\times10^4}{6\times86400\times.011224\times104.7}[/tex]
K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹
