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X-rays with a wavelength of 0.0711 nm create a diffraction pattern when they pass through a protein crystal. If the angular spacing between adjacent bright spots (m=0 and m=1) in the diffraction pattern is 28.9°, what is the average spacing between atoms in the crystal?

Respuesta :

Answer:

The average spacing between atoms in the crystal is [tex]1.47\times10^{-10}\ m [/tex].

Explanation:

Given that,

Wavelength = 0.0711 nm

Diffraction pattern = 28.9°

We need to calculate the average spacing between atoms in the crystal

Using formula of distance

[tex]d\sin\theta=m\lambda[/tex]

[tex]d=\dfrac{m\lambda}{\sin\theta}[/tex]

Here, m = 1

Put the value into the formula

[tex]d=\dfrac{1\times0.0711\times10^{-9}}{\sin28.9}[/tex]

[tex]d=1.47\times10^{-10}\ m [/tex]

Hence, The average spacing between atoms in the crystal is [tex]1.47\times10^{-10}\ m [/tex].

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