Answer:
when train is approaching then the frequency is 239.2 Hz
when train is moving away then the frequency is 195.25 Hz
Explanation:
given,
speed of train = 34.5 m/s
Frequency of sound = 215 Hz
speed of sound = 341 m/s
a) when train is approaching
[tex]f_1 = f(\dfrac{V}{V-V_t})[/tex]
[tex]f_1 = 215(\dfrac{341}{341-34.5})[/tex]
f₁ = 239.2 Hz
when train is approaching then the frequency is 239.2 Hz
b) when the train is moving away
[tex]f_2 = f(\dfrac{V}{V+V_t})[/tex]
[tex]f_2 = 215(\dfrac{341}{341+34.5})[/tex]
f₂ = 195.25 Hz
when train is moving away then the frequency is 195.25 Hz