Answer:
Wavelength will be [tex]0.464\mu m[/tex]
Explanation:
We have given distance between the two slits [tex]d=1.5\times 10^{-2}mm=1.5\times 10^{-5}m[/tex]
Angle [tex]\Theta =8.9^{\circ}[/tex]
We know that for nth order fringe [tex]dsin\Theta =n\lambda[/tex]
In question it is given that 5th order so n =5
So [tex]1.5\times 10^{-5}sin\8.9 =5\lambda[/tex]
[tex]\lambda =.464\times 10^{-6}m=0.464\mu m[/tex]
So wavelength will be [tex]0.464\mu m[/tex]
