Answer:
l = 0.8 m
gMars = 3.65 m/s2
Explanation:
The period of a pendulum depends on the length of it and the acceleration of gravity according to this equation:
[tex]T = 2 \pi \sqrt{\frac{l}{g}}[/tex]
If the pendulum has a period of 1.8s on Earth, the length must be:
[tex]l = g * (\frac{T}{2\pi})^2 = 9.81 * (\frac{1.8}{2\pi})^2 = 0.8 m[/tex]
If it has a period of 2.94 s on Mars, the gravity must be:
[tex]g = \frac{l}{(\frac{T}{2\pi})^2} = \frac{4 \pi^2 l}{T^2} = \frac{4 \pi^2 * 0.8}{2.94^2} = 3.65 \frac{m}{s^2}[/tex]
