Answer:8.37 min
Explanation:
Given
mass of water(m)=97 gm
Heater labelled as 63 Watt
Change in temperature of water=100-22=[tex]78^{\circ}[/tex]
Heat required to raise temperature is
[tex]Q=mc\left ( \Delta T\right )[/tex]
[tex]Q=0.097\times 4186\times \left ( 78\right )[/tex]
Q=31,671.276 J
This energy is given by Heater
E=Pt
[tex]63\times t=31,671.276[/tex]
[tex]t=\frac{31,671.276}{63}[/tex]
t=502.71 s
t=8.37 min
