Respuesta :
Answer:
30.93 m/s
Explanation:
Given that, the speed of stolen car is,
[tex]v_{s} =108km/hr\\v_{s} =108\times \frac{5}{18}m/s\\ v_{s} =30m/s[/tex]
As policeman start chasing the stolen car after 60 seconds.
Now suppose the speed of policeman car is, [tex]v_{p}[/tex]
The policeman catches the stolen car at a distance of,
[tex]S=60km\\S=60000m[/tex]
Now the distance covered by the policeman in time t is [tex]v_{p}\times t[/tex]
And the distane cover by the thief in stolen car in time(t+60s) is [tex]v_{s}\times (t+60sec)[/tex].
And these distances are equal and they are equal to 60000 m.
Therefore,
[tex]v_{p}\times t=v_{s}\times (t+60sec)=60000m[/tex]
Therfore,
[tex]v_{s}\times (t+60sec)=60000m\\30m/s\times (t+60sec)=60000m\\(t+60s)=2000s\\t=1940s[/tex]
Now use this value to solve for minimum speed of policeman's car.
[tex]v_{p}\times 1940=60000\\v_{p}=30.93 m/s[/tex]
Therefore minimum speed of policeman's car is 30.93 m/s.
