Answer:
[tex]I=3.75\times 10^5 W/m^2[/tex]
Explanation:
Given that
Diameter of laser beam d= 2.4 mm
Radius of laser beam r= 1.2 mm
Power P =1.7 W
We know that intensity(I) of laser beam given as follows
[tex]I=\dfrac{P}{\pi r^2}[/tex]
Now by putting the values
[tex]I=\dfrac{P}{\pi r^2}[/tex]
[tex]I=\dfrac{1.7}{\pi \times 0.0012^2}[/tex]
So
[tex]I=3.75\times 10^5 W/m^2[/tex]
So the intensity at 1.76 m away from laser
[tex]I=3.75\times 10^5 W/m^2[/tex]
