Answer:
The induced voltage in the Secondary is 18 volt.
Explanation:
Given that,
Voltage = 120 volt
Number of turns in primary = 500
Number of turns in secondary = 75
We need to calculate the induced voltage in the Secondary
Using relation number of turns and voltage in primary and secondary
[tex]\dfrac{V_{p}}{V_{s}}=\dfrac{N_{p}}{N_{s}}[/tex]
Where, [tex]N_{p}[/tex] = Number of primary coil
[tex]N_{s}[/tex] = Number of secondary coil
[tex]V_{p}[/tex] = Voltage of primary coil
[tex]V_{p}[/tex] = Voltage of primary coil
Put the value into the formula
[tex]\dfrac{120}{V_{s}}=\dfrac{500}{75}[/tex]
[tex]V_{s}=\dfrac{120\times75}{500}[/tex]
[tex]V_{s}=18\ Volt[/tex]
Hence, The induced voltage in the Secondary is 18 volt.
