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A tank whose bottom is a mirror is filled with water to a depth of 20.6 cm . A small fish floats motionless 7.80 cm under the surface of the water. Part A
What is the apparent depth of the fish when viewed at normal incidence to the water?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.
Part B
What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.

Respuesta :

Based on the information given, the depth will be 5.86 cm.

How to calculate the depth.

From the information given, the tank whose bottom is a mirror is filled with water to a depth of 20.6 cm and small fish floats motionless 7.80 cm under the surface of the water.

Based on the information given, the depth will be calculated thus:

= 7.80/d = 1.33

1.33d = 7.80

d = 7.80/1.33

d = 5.86 cm.

In conclusion, the apparent depth of the fish when viewed at normal incidence to the water is 5.86 cm.

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