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A proton, an electron, and a helium nucleus all move at speed v. Rank their de Broglie wavelengths from largest to smallest. Write any relevant formulas you use below. (a) helium nucleus, proton, electron (b) helium nucleus, electron, proton (c) electron, proton, helium nucleus (d) proton, electron, helium nucleus (e) proton, helium nucleus, electron

Respuesta :

Answer:

option (c)

Explanation:

mass of proton = mp = 1.6 x 10^-27 kg

mass of electron, me = 9.1 x 10^-31 kg

mass of helium nucleus, mHe = 6.6 x 10^-27 kg

Let the velocity of all the particles is v which is same .

Use the formula of de Broglie wavelength.

[tex]\lambda =\frac{h}{mv}[/tex]

Where, h be the Plank's constant and m be the mass of the particle and v be the velocity of particle.

Here, we observe that the de Broglie wavelength is inversely proportional to the mass of the particle.

Lesser be the mass more be the de broglie wavelength.

Here, mass of electron < mass of proton < mass of helium nucleus

So, de broglie wavelength of electron > de broglie wavelength of proton > de broglie wavelength of helium nucleus

Thus, option (c) is correct

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