Answer:
The force at a distance of 3.66 cm from [tex]q_1[/tex] will be zero
Explanation:
Electric force experienced will be zero where electric field will be zero .
We have given charges [tex]q_1\ and\ q_2=3q_1[/tex]
Distance between the charges = 10 cm
Let at d distance from q_1 electric field will be zero , so distance from q_2 =10-d
According to coulombs law electric field is given by
[tex]E=\frac{KQ}{R^2}[/tex]
[tex]\frac{Kq_1}{d^2}=\frac{K3q_1}{(10-d)^2}[/tex]
[tex]\frac{(10-d)}{d}=\sqrt{\frac{3q_1}{q_1}}[/tex]
[tex]10-d=1.732d[/tex]
d = 3.66 cm
So the force at a distance of 3.66 cm from [tex]q_1[/tex] will be zero