A torque of 12 N*m is applied to a solid uniform disk of radius 0.50 m. If the disk accelerates at 2.6 rad/s^2 what is the mass of the disk? A) 26 kg B) 25kg C) 17 kg D) 34 kg

Respuesta :

Answer:

mass = 36.92 kg

Explanation:

We have given the torque [tex]\tau =12 N-m[/tex]

Radius of the disk r = 0.50 m

Angular acceleration [tex]\alpha =2.6rad/sec^2[/tex]

We know that torque is given by [tex]\tau =I\alpha[/tex] here I is moment of inertia and [tex]\alpha[/tex] is angular acceleration

So [tex]12=I\times 2.6[/tex]

[tex]I=\frac{12}{2.6}=4.6153kgm^2[/tex]

Moment of inertia is given by [tex]I=\frac{1}{2}mr^2[/tex]

[tex]4.6153=\frac{1}{2}m0.5^2[/tex]

m = 36.92 kg

The given answer is not matched with this answer but after calculation i got m =36.92 kg