Answer:
option C
Explanation:
given,
a rectangular loop of wire = 6 cm × 8 cm
magnetic field = 1.3 T
loop rotated from zero flux to maximum in 21 ms
to calculate average induced emf :
area of loop = 0.06 × 0.08 = 4.8 × 10⁻³ m²
maximum magnetic flux Φ₂ = B × A
= 1.3 × 4.8 × 10⁻³ = 6.24 × 10⁻³ Wb
Ф₁ = 0
time taken to change the position from Ф₁ to Φ₂ is 21 ms
average indused emf = [tex]\frac{\mathrm{d} \phi}{\mathrm{d} t}[/tex]
= [tex]\dfrac{6.24 \times 10^{-3}-0}{21 \times 10^{-3}}[/tex]
= 0.297 = 0.3 V
hence, the correct answer is option C