Answer: Option c.
Explanation:
You need to use the following Kinematic equation:
[tex]V_f=V_0+at[/tex]
Where [tex]V_f[/tex] is the final velocity, [tex]V_0[/tex] is the initial velocity, [tex]a[/tex] is the acceleration and [tex]t[/tex] is the time.
In this case, you can identify that:
[tex]V_0=0\ (it\ accelerates\ from\ rest)\\\\a=50.0\ \frac{m}{s^2}\\\\t=1\ min=60\ s[/tex]
Therefore, substituting these values into the formula, you get:
[tex]V_f=0+(50.0\ \frac{m}{s^2})(60\ s)\\\\V_f=3,000\ \frac{m}{s}\\\\V_f=3.00*10^3\ \frac{m}{s}[/tex]
