Answer:
(c) 97 dB sound intensity level
Explanation:
We have given the intensity of the loud car horn [tex]I=0.005w/m^2[/tex]
We know that [tex]I_O=10^{-12}w/m^2[/tex]
Now the sound intensity level is given by [tex]\beta =10log\frac{I}{I_0}=10log\frac{0.005}{10^{-12}}=96.98dB[/tex] , which is nearly equal to 97
So the sound intensity level will be 97 dB
So option (c) will be the correct option