An all-electric home uses approximately 1760 kWh of electric energy per month. How much uranium-235 would be required to provide this house with its energy needs for one year? Assume 100% conversion efficiency and 208 MeV released per fission.

Respuesta :

Answer:

mass of U 235 is 8.92 × [tex]10^{-4}[/tex] gram

Explanation:

given data

electric energy = 1760 kWh per month

energy u 235 = 208 MeV

to find out

mass of u 235

solution

we know here energy consume in a year is

energy consume = 1760 × 10³ ×3600 × 12

energy consume = 7.603 × [tex]10^{10}[/tex] J

and

now we find no of u235 atom by burn require energy is

that is = energy consume / energy

= 7.603 × [tex]10^{10}[/tex] / ( 208 × 1.6 × [tex]10^{-13}[/tex] )

= 2.285 × [tex]10^{18}[/tex]

and we know 1 mole of  u235 = 6.02 × [tex]10^{23}[/tex] atoms

so mass of U235 is

mass = 2.285 × [tex]10^{18}[/tex]  /   ( 6.02 × [tex]10^{23}[/tex] )

mass of U 235 = 8.92 × [tex]10^{-4}[/tex] gram