Respuesta :
Answer:
The correct answer is option 'a': 2v
Explanation:
For a object under pure rolling the velocity of any point is given by
[tex]v_{rolling}=v_{translational}+v_{rotational}[/tex]
Since in case of pure rolling the angular velocity is related to the transnational velocity as
[tex]\omega =\frac{v_{translational}}{r}[/tex]
positive value is taken as the velocities have the same direction.
Thus the rotational velocity is given by
[tex]v_{rotational}=\omega \times r\\\\\\v_{rotational}=\frac{V_{trans}}{r}\times r\\\\v_{rotational}=v_{trans}[/tex]
Thus the velocity at the tip becomes
[tex]v_{rolling}=v+v\\\\v_{rolling}=2v[/tex]
Answer:
2V.
Explanation:
We know rolling motion is superposition of rotational and translational motion.
Also, it is rolling without slipping.
Therefore, [tex]V=\omega \times R[/tex] .....1
Where, V is linear velocity and [tex]\omega[/tex] is angular velocity of tire.
Now, at the top point :
Its, linear velocity is V because the tire it is moving with a velocity V.
Now , it is at a distance R from the center of tire.
Its , Velocity due to rotation [tex]V_r=\omega \times R[/tex]. {because is is not slipping}.
Both these velocities are in same direction.
Therefore, [tex]V_t=V+V_r\\V_t=V+V=2V[/tex]
Because, [tex]V_r=V[/tex] ( from 1)
Hence, it is the required solution.
