Answer:
area of the plates is 0.01802 m²
Explanation:
given,
charge between the plate = 7.58 × 10⁻⁹ C
electric field = 47500 N/C
E = [tex]\dfrac{V}{d}[/tex]
V = E× d
charge on the plate
Q = C V
Q =[tex]\dfrac{\varepsilon _0 A}{d}\times V[/tex]
Q = ∈₀ × A × E
A = [tex]\dfrac{Q}{\varepsilon _0 E}[/tex]
A = [tex]\dfrac{7.58 \times 10^{-9}}{8.854\times 10^{-12} \times 47500}[/tex]
A = 0.01802 m²
hence, area of the plates is 0.01802 m²
