Respuesta :
Answer:
The source voltage is 578.57 V.
Explanation:
Given that,
Frequency = 60 Hz
Resistor = 705 Ω
Capacitor = 6.9 μF
Power = 183 W
We need to calculate the source voltage amplitude
Using formula of power
[tex]W=I^2R[/tex]
[tex]W=(\dfrac{V}{\sqrt{R^2+\dfrac{1}{\omega^2 C^2}}})^2 R[/tex]
[tex]W=\dfrac{1}{2}\dfrac{V^2 R}{R^2+\dfrac{1}{\omega^2C^2}}[/tex]
[tex]V=\sqrt{2W\dfrac{R^2+\dfrac{1}{\omga^2C^2}}{R}}[/tex]
Where, R = resistor
C = capacitor
W = power
Put the value into the formula
[tex]V=\sqrt{2\times183\dfrac{705^2+\dfrac{1}{4\pi^260^2\times(6.9\times10^{-6})^2}}{705}}[/tex]
[tex]V=578.57\ V[/tex]
Hence, The source voltage is 578.57 V.
