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A series R-L-C circuit is connected to a 110 Hz ac source that has Vrms = 80.0 V . The circuit has a resistance of 65.0 Ω and an impedance of 104 Ω at this frequency. What average power is delivered to the circuit by the source?

Respuesta :

Answer:

Power P =38.46 W

Explanation:

We have given the voltage [tex]V_{rms}=80V[/tex]

Resistance R = 65 ohm

Impedance Z = 104 ohm

According to ohm's law current [tex]i=\frac{V}{Z}=\frac{80}{104}=0.7692A[/tex]

Power factor [tex]cos\Phi =\frac{R}{Z}=\frac{65}{104}=0.625[/tex]

Power delivered by the source P [tex]Vicos\Phi =80\times 0.7692\times 0.625=38.46W[/tex]  

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