Answer:
Wavelength, [tex]\lambda=1.28\times 10^{-14}\ m[/tex]
Explanation:
Given that,
Mass of the particle, [tex]m=4.3\times 10^{-28}\ kg[/tex]
Acceleration of the particle, [tex]a=2.4\times 10^7\ m/s^2[/tex]
Time, t = 5 s
It starts from rest, u = 0
The De Broglie wavelength is given by :
[tex]\lambda=\dfrac{h}{mv}[/tex]
v = a × t
[tex]\lambda=\dfrac{h}{mat}[/tex]
[tex]\lambda=\dfrac{6.67\times 10^{-34}}{4.3\times 10^{-28}\times 2.4\times 10^7\times 5}[/tex]
[tex]\lambda=1.28\times 10^{-14}\ m[/tex]
Hence, this is the required solution.
