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A chemist measures the amount of bromine liquid produced during an experiment. She finds that 14.4 g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced.
Round your answer to 3 significant digit

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Answer:

[tex]\boxed{\text{0.0901 mol}}[/tex]

Explanation:

[tex]\text{Moles} = \text{14.4 g } \times \dfrac{\text{1 mol}}{\text{159.81 g}} = \text{0.0901 mol}\\\\\text{ The sample contains $\boxed{\textbf{0.0901 mol}}$ of bromine}[/tex]

Eduard22sly

The number of mole of bromine liquid produced is 0.09 mole  

The mole of an element as it relates to its mass and molar mass, can be obtained by using the following equation:

Mole = mass / molar mass

With the above formula, we can obtain the number of mole bromine liquid produced. This can be obtained as follow:

Mass of bromine liquid (Br₂) = 14.4 g

Molar mass of bromine liquid (Br₂) = 2 × 80 = 160 g/mol

Mole of bromine liquid (Br₂) =?

Mole = mass / molar mass

Mole of bromine liquid = 14.4 / 160

Mole of bromine liquid = 0.09 mole

Therefore, the number of mole of bromine liquid produced is 0.09 mole

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